60 words can be made using all the letters of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) The word is $BHBJO$. The letters are $B, B, H, J, O$. Total letters = $5$. The number of arrangements is $\frac{5!}{2!} = \frac{120}{2} = 60$.To f

Vedclass · Accepted Answer

$OBBJH$

Vedclass · Answer

(C) The word is $BHBJO$. The letters are $B, B, H, J, O$. Total letters = $5$. The number of arrangements is $\frac{5!}{2!} = \frac{120}{2} = 60$.To find the $50^{	ext{th}}$ word,we arrange them alphabetically: $B, B, H, J, O$.$1$. Words starting with $B$: $\frac{4!}{1!} = 24$ words.$2$. Words starting with $H$: $\frac{4!}{2!} = 12$ words. (Total = $24 + 12 = 36$)$3$. Words starting with $J$: $\frac{4!}{2!} = 12$ words. (Total = $36 + 12 = 48$)$4$. Words starting with $O$:- $OBBJH$ $(49^{	ext{th}})$- $OBBJH$ is not correct,let's list $O$ words:- $OBBHJ$ $(49^{	ext{th}})$- $OBBJH$ $(50^{	ext{th}})$Thus,the $50^{	ext{th}}$ word is $OBBJH$.

$60$ words can be made using all the letters of the word $BHBJO$,with or without meaning. If these words are written as in a dictionary,then the $50^{\text{th}}$ word is:

Similar Questions

If the letters of the word $RACHIT$ are arranged in all possible ways and these words are listed in dictionary order,what is the rank of the word $RACHIT$?

If the letters of the word $KRISNA$ are arranged in all possible ways and these words are written out as in a dictionary,then the rank of the word $KRISNA$ is

How many words can be formed using the letters of the word $ARTICLE$ if the vowels always occupy even positions?

The number of ways in which $3$ men and $3$ women can be arranged in a row of $6$ seats,such that the first and last seats must be filled by men is

Find $n$ if $^{n-1}P_{3} : ^{n}P_{4} = 1 : 9$.

Vedclass Test Series

Exam Paper Generator

Online Exam Module