$STATEMENT-1:$ There is a natural asymmetry between converting work to heat and converting heat to work.
$STATEMENT-2:$ No process is possible in which the sole result is the absorption of heat from a reservoir and its complete conversion into work.

  • A
    $STATEMENT-1$ is True,$STATEMENT-2$ is True; $STATEMENT-2$ is correct explanation for $STATEMENT-1$
  • B
    $STATEMENT-1$ is True,$STATEMENT-2$ is True; $STATEMENT-2$ is $NOT$ a correct explanation for $STATEMENT-1$
  • C
    $STATEMENT-1$ is True,$STATEMENT-2$ is False
  • D
    $STATEMENT-1$ is False,$STATEMENT-2$ is True

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Similar Questions

Given the entropy of $H_2$ and $HBr$ are $130.6 \, JK^{-1}$ and $198.5 \, JK^{-1}$ respectively,calculate the entropy of $Br_{2(g)}$ in the reaction $H_{2(g)} + Br_{2(g)} \rightarrow 2HBr_{(g)}$ where $\Delta S^{o} = 20.1 \, JK^{-1}$.

In which of the following processes is $\Delta S$ negative?

For the reaction $H_2O_{(l)} \longrightarrow H_2O_{(g)}$ at $T=100^{\circ} C$ and $P=1 \ atm$,choose the correct option:

The enthalpy change for the transition of liquid water to steam is $37.3 \ kJ \ mol^{-1}$ at $373 \ K$. Find $\Delta S$ in $J \ mol^{-1} \ K^{-1}$.

Direct conversion of $A$ to $B$ is difficult,so it is carried out by the path shown below. If $e.u.$ is the entropy unit,what will be $\Delta S_{(A \rightarrow B)}$?
Given:
$\Delta S_{(A \rightarrow C)} = 50 \ e.u.$
$\Delta S_{(C \rightarrow D)} = 30 \ e.u.$
$\Delta S_{(B \rightarrow D)} = 20 \ e.u.$

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