$A$ and $B$ alternately throw a pair of dice. $A$ wins if he throws a sum of $5$ before $B$ throws a sum of $8$,and $B$ wins if he throws a sum of $8$ before $A$ throws a sum of $5$. The probability that $A$ wins,if $A$ makes the first throw,is

  • A
    $\frac{9}{17}$
  • B
    $\frac{9}{19}$
  • C
    $\frac{8}{17}$
  • D
    $\frac{8}{19}$

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