Medium
$A$ series $LCR$ circuit is connected to an alternating source of emf $E$. The current amplitude at resonant frequency is $I_0$. If the value of resistance $R$ becomes twice of its initial value,then the amplitude of current at resonance will be
- A$I_0$
- B$\frac{I_0}{2}$
- C$\frac{I_0}{\sqrt{2}}$
- D$2 I_0$
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Medium
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