A time-varying potential difference is applie | vedclass

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(D) The displacement current $I_d$ in a capacitor is given by the formula: $I_d = C \frac{dV}{dt}$.Here,$C = 2.5 \mu 	ext{F} = 2.5 	imes 10^{-6} 	e

Vedclass · Accepted Answer

$100$

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(D) The displacement current $I_d$ in a capacitor is given by the formula: $I_d = C \frac{dV}{dt}$.Here,$C = 2.5 \mu 	ext{F} = 2.5 	imes 10^{-6} 	ext{ F}$ and $I_d = 0.25 	ext{ mA} = 0.25 	imes 10^{-3} 	ext{ A}$.Rearranging the formula to find the rate of change of potential difference $\frac{dV}{dt}$:$\frac{dV}{dt} = \frac{I_d}{C}$.Substituting the given values:$\frac{dV}{dt} = \frac{0.25 	imes 10^{-3}}{2.5 	imes 10^{-6}}$.$\frac{dV}{dt} = \frac{0.25}{2.5} 	imes 10^{3} = 0.1 	imes 1000 = 100 	ext{ V s}^{-1}$.Thus,the magnitude of the rate of change of the potential difference is $100 	ext{ V s}^{-1}$.

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