A plano-convex lens having a radius of curvat | vedclass

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(B) For a plano-convex lens,the lens maker's formula is given by $\frac{1}{f} = (\mu_g - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$. For a plano

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$1: 3$

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(B) For a plano-convex lens,the lens maker's formula is given by $\frac{1}{f} = (\mu_g - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} ight)$. For a plano-convex lens,$R_1 = R$ and $R_2 = \infty$.For the first lens in air $(\mu_a = 1)$:$\frac{1}{f_1} = (1.5 - 1) \left( \frac{1}{2} - 0 ight) = 0.5 	imes 0.5 = 0.25$$f_1 = 4 \ cm$.For the second lens in liquid $(\mu_l = 1.2)$:$\frac{1}{f_2} = \left( \frac{\mu_g}{\mu_l} - 1 ight) \left( \frac{1}{R_1} - 0 ight) = \left( \frac{1.5}{1.2} - 1 ight) \left( \frac{1}{3} ight)$$\frac{1}{f_2} = (1.25 - 1) 	imes \frac{1}{3} = 0.25 	imes \frac{1}{3} = \frac{1}{4} 	imes \frac{1}{3} = \frac{1}{12}$$f_2 = 12 \ cm$.The ratio $f_1 : f_2 = 4 : 12 = 1 : 3$.

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