A capacitor,C_1 = 6 mu F is charged to a pot | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) Initially,the charge on capacitor $C_1$ is $q_{initial} = C_1 V_0 = 6 \ \mu F 	imes 5 \ V = 30 \ \mu C$. The charge on $C_2$ is $0 \ \mu C$.When

Vedclass · Accepted Answer

$q_1 = 10 \ \mu C, q_2 = 20 \ \mu C$

Vedclass · Answer

(B) Initially,the charge on capacitor $C_1$ is $q_{initial} = C_1 V_0 = 6 \ \mu F 	imes 5 \ V = 30 \ \mu C$. The charge on $C_2$ is $0 \ \mu C$.When the switch $S$ is closed,the charge redistributes until both capacitors reach a common potential $V_c$. By the law of conservation of charge,the total charge remains constant:$q_{total} = q_1 + q_2 = 30 \ \mu C + 0 \ \mu C = 30 \ \mu C$.At equilibrium,$q_1 = C_1 V_c$ and $q_2 = C_2 V_c$. Since they are connected in parallel,$V_c = \frac{q_{total}}{C_1 + C_2} = \frac{30 \ \mu C}{6 \ \mu F + 12 \ \mu F} = \frac{30}{18} \ V = \frac{5}{3} \ V$.Now,calculate the final charges:$q_1 = C_1 V_c = 6 \ \mu F 	imes \frac{5}{3} \ V = 10 \ \mu C$.$q_2 = C_2 V_c = 12 \ \mu F 	imes \frac{5}{3} \ V = 20 \ \mu C$.

Similar Questions

Initially, $n$ identical capacitors are joined in parallel, and are charged to potential $V$. Now they are separated and joined in series. Then:

In the circuit shown in the figure,the charge stored in the capacitor of capacity $5 \ \mu F$ is......$ \mu C$.

Two particles of equal mass $m$ have charges $+q$ and $+4q$. If they are accelerated through the same potential difference $V$,the ratio of their velocities $\frac{v_A}{v_B}$ is:

$A$ parallel plate capacitor is charged fully by using a battery. Then,without disconnecting the battery,the plates are moved further apart. Then,

Vedclass Test Series

Exam Paper Generator

Online Exam Module