$A$ physical quantity $Q$ is related to four observables $a, b, c, d$ as follows: $Q = \frac{ab^4}{cd}$,where $a = (60 \pm 3) \ Pa$,$b = (20 \pm 0.1) \ m$,$c = (40 \pm 0.2) \ Nsm^{-2}$,and $d = (50 \pm 0.1) \ m$. The percentage error in $Q$ is $\frac{x}{1000}$,where $x = $ . . . . . . .

The current-voltage relation of a diode is given by $I = (e^{1000V/T} - 1) \text{ mA}$,where the applied voltage $V$ is in volts and the temperature $T$ is in Kelvin. If a student makes an error of $\pm 0.01 \text{ V}$ while measuring the voltage to obtain a current of $5 \text{ mA}$ at $300 \text{ K}$,what will be the error in the value of current in $\text{mA}$?

The most accurate reading of the length of a $6.28 \,cm$ long fibre is ............... $cm$.

In an experiment for the measurement of $g$ using a simple pendulum,the time period was measured with an accuracy of $0.2 \%$ while the length was measured with an accuracy of $0.5 \%$. The percentage accuracy in the value of $g$ thus obtained is: (in $\%$)

The acceleration due to gravity is found up to an accuracy of $4\,\%$ on a planet. The energy supplied to a simple pendulum of known mass '$m$' to undertake oscillations of time period $T$ is being estimated. If the time period is measured to an accuracy of $3\,\%$,the accuracy to which $E$ is known is $..........\,\%$.

In an experiment,four quantities $p, q, r$,and $s$ are measured with percentage errors of $3 \%, 2 \%, 3 \%$,and $1 \%$ respectively. Quantity $A$ is calculated as follows: $A = \frac{pq^2}{r^2 s^4}$. The percentage error in $A$ is: (in $\%$)