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Question

(A) The target molecule "$x$" is $1$-acetylcyclopent$-1-$ene. To obtain this via an intramolecular aldol condensation,the precursor must be a dicarbon

Vedclass · Accepted Answer

$1-$methylcyclohex$-1-$ene

Vedclass · Answer

(A) The target molecule "$x$" is $1$-acetylcyclopent$-1-$ene. To obtain this via an intramolecular aldol condensation,the precursor must be a dicarbonyl compound,specifically $6$-oxoheptanal. Ozonolysis of $1$-methylcyclohex$-1-$ene ($1$-methylcyclohexene) breaks the double bond to form $6$-oxoheptanal $(CH_3COCH_2CH_2CH_2CH_2CHO)$. This dicarbonyl compound undergoes intramolecular aldol condensation in the presence of $OH^{\ominus}/\Delta$ to form the five-membered ring product,$1$-acetylcyclopent$-1-$ene. Thus,the correct starting alkene is $1$-methylcyclohex$-1-$ene.

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