A person measures the mass of 3 different par | vedclass

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(C) The given masses are $m_1 = 435.42 \ g$,$m_2 = 226.3 \ g$,and $m_3 = 0.125 \ g$.To find the sum,we add them: $435.42 + 226.3 + 0.125 = 661.845 \ g

Vedclass · Accepted Answer

$661.8$

Vedclass · Answer

(C) The given masses are $m_1 = 435.42 \ g$,$m_2 = 226.3 \ g$,and $m_3 = 0.125 \ g$.To find the sum,we add them: $435.42 + 226.3 + 0.125 = 661.845 \ g$.According to the rules for addition with significant figures,the final result should be reported to the same number of decimal places as the measurement with the fewest decimal places.The measurements have $2$,$1$,and $3$ decimal places respectively. The least number of decimal places is $1$.Therefore,rounding $661.845 \ g$ to one decimal place gives $661.8 \ g$.

$A$ person measures the mass of $3$ different particles as $435.42 \ g$,$226.3 \ g$,and $0.125 \ g$. According to the rules for arithmetic operations with significant figures,the sum of the masses of the $3$ particles will be: (in $g$)

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