A conductor ABCD is moving with speed V along | vedclass

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(D) The induced electromotive force $(emf)$ in a conductor moving in a magnetic field is given by the formula $e = B \cdot L_{\perp} \cdot V$, where $

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$BC$

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(D) The induced electromotive force $(emf)$ in a conductor moving in a magnetic field is given by the formula $e = B \cdot L_{\perp} \cdot V$, where $L_{\perp}$ is the effective length of the conductor perpendicular to the velocity vector $V$.Since the velocity $V$ is along the $X$-axis, the effective length $L_{\perp}$ is the projection of the conductor segment onto the $Y$-axis (vertical distance between the points).Comparing the vertical distances between the given points:For $AB$, the vertical distance is small.For $BD$, the vertical distance is the sum of the vertical heights of $BC$ and $CD$.For $BC$, the vertical distance is the maximum vertical span of the curve between these two points.Looking at the geometry of the sine-like curve, the vertical distance between $B$ and $C$ is the largest among the options provided, as it spans from the peak to the trough of the wave.Therefore, the maximum induced $emf$ is produced between points $B$ and $C$.

$A$ conductor $ABCD$ is moving with speed $V$ along the $X$-axis in a region where the magnetic field is uniform and directed into the plane of the paper. Between which points is the maximum induced emf produced?

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