A step-down transformer transforms 220 text{ | vedclass

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(D) The efficiency $(\eta)$ of a transformer is defined as the ratio of output power to input power.$\eta = \frac{P_{	ext{out}}}{P_{	ext{in}}} 	ime

Vedclass · Accepted Answer

$90$

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(D) The efficiency $(\eta)$ of a transformer is defined as the ratio of output power to input power.$\eta = \frac{P_{	ext{out}}}{P_{	ext{in}}} 	imes 100 = \frac{V_s I_s}{V_p I_p} 	imes 100$Given:Primary voltage $(V_p)$ = $220 	ext{ V}$Secondary voltage $(V_s)$ = $11 	ext{ V}$Primary current $(I_p)$ = $5 	ext{ A}$Secondary current $(I_s)$ = $90 	ext{ A}$Substituting the values:$\eta = \frac{11 	imes 90}{220 	imes 5} 	imes 100$$\eta = \frac{990}{1100} 	imes 100 = 0.9 	imes 100 = 90 \%$

$A$ step-down transformer transforms $220 \text{ V}$ to $11 \text{ V}$. If the currents in the primary and secondary coils are $5 \text{ A}$ and $90 \text{ A}$ respectively,the efficiency of the transformer is: (in $\%$)

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