$A$ string just breaks under a load of $50 \ kg$. $A$ mass of $1 \ kg$ is attached to one end of this string $10 \ m$ long and is rotated in a horizontal circle. Calculate the greatest number of revolutions that the mass can make in one second without breaking the string. (Take $g = 10 \ m/s^2$)

• A
  $\frac{2 \pi}{\sqrt{50}} \text{ rps}$
• B
  $\frac{\sqrt{50}}{2 \pi} \text{ rps}$
• C
  $\frac{\sqrt{55}}{2 \pi} \text{ rps}$
• D
  $\frac{\sqrt{60}}{2 \pi} \text{ rps}$