A quantity of heat Q is supplied to a monoato | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) For an isobaric process,the heat supplied is given by $\Delta Q = \mu C_p \Delta T$. According to the first law of thermodynamics,$\Delta Q = \Del

Vedclass · Accepted Answer

$2/5$

Vedclass · Answer

(A) For an isobaric process,the heat supplied is given by $\Delta Q = \mu C_p \Delta T$. According to the first law of thermodynamics,$\Delta Q = \Delta U + \Delta W$,where $\Delta U = \mu C_v \Delta T$ is the change in internal energy and $\Delta W$ is the work done. Thus,$\Delta W = \Delta Q - \Delta U = \mu C_p \Delta T - \mu C_v \Delta T = \mu (C_p - C_v) \Delta T$. The fraction of heat converted into work is $f = \frac{\Delta W}{\Delta Q} = \frac{\mu (C_p - C_v) \Delta T}{\mu C_p \Delta T} = 1 - \frac{C_v}{C_p} = 1 - \frac{1}{\gamma}$. For a monoatomic gas,the adiabatic index $\gamma = 5/3$. Therefore,$f = 1 - \frac{1}{5/3} = 1 - \frac{3}{5} = \frac{2}{5}$.

$A$ quantity of heat $Q$ is supplied to a monoatomic ideal gas which expands at constant pressure. The fraction of heat that goes into work done by the gas is

Similar Questions

Obtain the expression for work done by a gas during an isobaric process (constant pressure).

In an isobaric process of an ideal gas,the ratio of heat supplied and work done by the system $\left(\frac{Q}{W}\right)$ is given by $\left[\frac{C_{P}}{C_{V}}=\gamma\right]$.

Given the relation $V = K \left( \frac{P}{T} \right)^{0.33}$,where $K$ is a constant. Identify the type of thermodynamic process.

The ratio of specific heats of a gas is $\gamma$. The change in internal energy of one mole of the gas, when the volume changes from $V$ to $2V$ at constant pressure $p$, is:

Volume versus temperature graph of two moles of helium gas is as shown in figure. The ratio of heat absorbed and the work done by the gas in process $1-2$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module