A current of 10 A flows through two long par | vedclass

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(A) The magnetic force per unit length between two long parallel wires is given by the formula:$F = \frac{\mu_0 i_1 i_2}{2 \pi d} = 2 	imes 10^{-3} \

Vedclass · Accepted Answer

$16$

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(A) The magnetic force per unit length between two long parallel wires is given by the formula:$F = \frac{\mu_0 i_1 i_2}{2 \pi d} = 2 	imes 10^{-3} \ N/m$When the currents are doubled ($i_1' = 2i_1$ and $i_2' = 2i_2$) and the separation is halved $(d' = d/2)$,the new force per unit length $F'$ is:$F' = \frac{\mu_0 (2i_1)(2i_2)}{2 \pi (d/2)}$$F' = \frac{4 \mu_0 i_1 i_2}{2 \pi (d/2)} = 8 	imes \left( \frac{\mu_0 i_1 i_2}{2 \pi d} ight)$Substituting the initial value of force:$F' = 8 	imes (2 	imes 10^{-3} \ N/m) = 16 	imes 10^{-3} \ N/m$Therefore,the new force per unit length is $16 	imes 10^{-3} \ N/m$.

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