A conducting sphere of radius R carrying a ch | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) The total charge of the system is $Q_{total} = q + (-2q) = -q$.When two conducting spheres are connected by a wire,charge flows until their potent

Vedclass · Accepted Answer

$\frac{4q}{3}$

Vedclass · Answer

(D) The total charge of the system is $Q_{total} = q + (-2q) = -q$.When two conducting spheres are connected by a wire,charge flows until their potentials become equal.Let the final charges on the spheres be $Q_1$ and $Q_2$ respectively.The potential of a sphere is given by $V = \frac{kQ}{r}$. Since $V_1 = V_2$,we have $\frac{kQ_1}{R} = \frac{kQ_2}{2R}$,which implies $\frac{Q_1}{Q_2} = \frac{1}{2}$,or $Q_2 = 2Q_1$.Since the total charge is conserved,$Q_1 + Q_2 = -q$.Substituting $Q_2 = 2Q_1$,we get $Q_1 + 2Q_1 = -q$,so $3Q_1 = -q$,which gives $Q_1 = -\frac{q}{3}$.The initial charge on the first sphere was $q$. The final charge is $-\frac{q}{3}$.The charge that flowed from the first sphere is $\Delta q = q_{initial} - q_{final} = q - (-\frac{q}{3}) = \frac{4q}{3}$.

$A$ conducting sphere of radius $R$ carrying a charge $q$ is joined by a conducting wire to a conducting sphere of radius $2R$ carrying a charge $-2q$. The charge flowing between them will be:

Similar Questions

$A$ capacitor of $20\,\mu F$ is charged to $500\,V$ and connected in parallel with another capacitor of $10\,\mu F$ which is charged to $200\,V$. The common potential is.......$V$.

The capacities of two conductors are $C_1$ and $C_2$ and their respective potentials are $V_1$ and $V_2$. If they are connected by a thin wire,then the loss of energy will be given by

$A$ capacitor of capacitance $C$ charged by an amount $Q$ is connected in parallel with an uncharged capacitor of capacitance $2C$. The final charges on the capacitors are

$A$ $2 \ \mu F$ capacitor is charged as shown in the figure. The percentage of its stored energy dissipated after the switch $S$ is turned to position $2$ is (in $\%$)

Two capacitors of $1\,\mu F$ and $2\,\mu F$ are charged to $1200\,V$. If they are connected in parallel such that the positive plate of one is connected to the negative plate of the other,what will be the new charge on each capacitor?

Vedclass Test Series

Exam Paper Generator

Online Exam Module