Isopropyl amine with an excess of acetyl chlo | vedclass

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Question

(C) The reaction of a primary amine with an excess of acetyl chloride $(CH_{3}COCl)$ in the presence of a base leads to diacylation. The reaction is:

Vedclass · Accepted Answer

$((CH_{3})_{2}CHN(COCH_{3})_{2})$

Vedclass · Answer

(C) The reaction of a primary amine with an excess of acetyl chloride $(CH_{3}COCl)$ in the presence of a base leads to diacylation. The reaction is: $(CH_{3})_{2}CHNH_{2} + 2CH_{3}COCl \rightarrow (CH_{3})_{2}CHN(COCH_{3})_{2} + 2HCl$. Here,the primary amine $(CH_{3})_{2}CHNH_{2}$ reacts with two equivalents of acetyl chloride to form $N,N$-diacetylisopropylamine,which is $((CH_{3})_{2}CHN(COCH_{3})_{2})$.

$Isopropyl$ amine with an excess of acetyl chloride will give:

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