A first order reaction has a rate constant 0. | vedclass

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Question

(C) For a first order reaction,the rate equation is given by $t = \frac{2.303}{k} \log_{10} \frac{[A]_0}{[A]_t}$.Given,rate constant $k = 0.00813 \ mi

Vedclass · Accepted Answer

$112.7$

Vedclass · Answer

(C) For a first order reaction,the rate equation is given by $t = \frac{2.303}{k} \log_{10} \frac{[A]_0}{[A]_t}$.Given,rate constant $k = 0.00813 \ min^{-1}$.Let the initial concentration $[A]_0 = 100$.For $60 \%$ completion,the amount reacted is $60$,so the remaining concentration $[A]_t = 100 - 60 = 40$.Substituting the values in the formula:$t = \frac{2.303}{0.00813} \log_{10} \frac{100}{40}$$t = \frac{2.303}{0.00813} \log_{10} (2.5)$$t = \frac{2.303}{0.00813} 	imes 0.3979$$t \approx 112.7 \ min$.

$A$ first order reaction has a rate constant $0.00813 \ min^{-1}$. How long will it take for $60 \%$ completion (in $min$)?

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