Ce^{4+} is stable. This is because of | vedclass

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(C) The electronic configuration of $Ce$ $(Z=58)$ is: $[Xe] 4f^{1} 5d^{1} 6s^{2}$.In the $+4$ oxidation state,$Ce^{4+}$ loses four electrons to achiev

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empty orbital

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(C) The electronic configuration of $Ce$ $(Z=58)$ is: $[Xe] 4f^{1} 5d^{1} 6s^{2}$.In the $+4$ oxidation state,$Ce^{4+}$ loses four electrons to achieve the stable noble gas configuration of $Xe$ $(Z=54)$.The configuration of $Ce^{4+}$ is $[Xe] 4f^{0} 5d^{0} 6s^{0}$.Since all valence orbitals $(4f, 5d, 6s)$ are empty,$Ce^{4+}$ attains the stable configuration of the nearest inert gas,making it highly stable.

$Ce^{4+}$ is stable. This is because of

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