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(B) The work done by the system during expansion is given by the formula: $W = -P_{ext} \Delta V$. Given: External pressure $P_{ext} = 2 	imes 10^5 \

Vedclass · Accepted Answer

$-40.0$

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(B) The work done by the system during expansion is given by the formula: $W = -P_{ext} \Delta V$. Given: External pressure $P_{ext} = 2 	imes 10^5 \ Nm^{-2}$ Change in volume $\Delta V = 200 \ cm^3 = 200 	imes 10^{-6} \ m^3 = 2 	imes 10^{-4} \ m^3$. Substituting the values: $W = -(2 	imes 10^5 \ Nm^{-2}) 	imes (2 	imes 10^{-4} \ m^3)$ $W = -40 \ J$. Therefore,the work done by the system is $-40 \ J$.

$A$ gas absorbs a certain amount of heat and expands by $200 \ cm^3$ against a constant external pressure of $2 \times 10^5 \ Nm^{-2}$. What is the work done by the system (in $J$)?

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