$y = mx + \frac{2}{m}$ is the general solution of

  • A
    $y\left(\frac{dy}{dx}\right)^{2} = x\left(\frac{dy}{dx}\right) + 2$
  • B
    $y = x \frac{dy}{dx} + 2$
  • C
    $y\left(\frac{dy}{dx}\right) = x\left(\frac{dy}{dx}\right)^{2} + 2$
  • D
    $y\left(\frac{dy}{dx}\right) = x + 2$

Explore More

Similar Questions

If $\alpha$ and $\beta$ are respectively the order and degree of the differential equation for which $a x^2+b y^2=1$ is the general solution, then the eccentricity of the ellipse $\alpha x^2+\beta y^2=1$ is

Verify that the given function $x^{2}=2 y^{2} \log y$ is a solution of the corresponding differential equation $(x^{2}+y^{2}) \frac{dy}{dx}-xy=0$.

The differential equation of the family of curves given by $y = a e^{2x} + b e^{5x}$,where $a$ and $b$ are parameters,is:

The general solution of the differential equation of all circles having center at $A(-1, 2)$ is $ . . . . . . $.

Among the options given below,from which option can a differential equation of order two be formed?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo