sim[(p vee sim q) rightarrow (p wedge sim q)] | vedclass

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(C) We use the logical equivalence $A \rightarrow B \equiv \sim A \vee B$ and De Morgan's Laws.Given expression: $\sim[(p \vee \sim q) \rightarrow (p

Vedclass · Accepted Answer

$(p \vee \sim q) \wedge (\sim p \vee q)$

Vedclass · Answer

(C) We use the logical equivalence $A \rightarrow B \equiv \sim A \vee B$ and De Morgan's Laws.Given expression: $\sim[(p \vee \sim q) \rightarrow (p \wedge \sim q)]$Applying the conditional law: $\sim[\sim(p \vee \sim q) \vee (p \wedge \sim q)]$Applying De Morgan's law: $(p \vee \sim q) \wedge \sim(p \wedge \sim q)$Applying De Morgan's law again: $(p \vee \sim q) \wedge (\sim p \vee q)$Thus,the correct option is $C$.

$\sim[(p \vee \sim q) \rightarrow (p \wedge \sim q)] \equiv$

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