A bakerman sells 5 types of cakes. Profit due | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The expected profit per cake is calculated using the formula for the expected value: $E(X) = \sum p_i x_i$.Here,$x_i$ represents the profit for ea

Vedclass · Accepted Answer

Rs $1.725$

Vedclass · Answer

(A) The expected profit per cake is calculated using the formula for the expected value: $E(X) = \sum p_i x_i$.Here,$x_i$ represents the profit for each type of cake and $p_i$ represents the probability (demand) of each type.Given values:$x_1 = 2, p_1 = 0.20$$x_2 = 2.5, p_2 = 0.05$$x_3 = 3, p_3 = 0.10$$x_4 = 1.5, p_4 = 0.50$$x_5 = 1, p_5 = 0.15$Expected Profit $= (2 	imes 0.20) + (2.5 	imes 0.05) + (3 	imes 0.10) + (1.5 	imes 0.50) + (1 	imes 0.15)$$= 0.4 + 0.125 + 0.3 + 0.75 + 0.15$$= 1.725$Therefore,the expected profit per cake is $Rs \ 1.725$.

$X$	$30$	$10$	$-10$
$P(X)$	$\frac{1}{5}$	$A$	$B$

Number of smart phones $(x)$	$0$	$1$	$2$	$3$	$4$	$5$
Probability $(P(x))$	$k$	$0.3$	$0.15$	$0.15$	$0.1$	$2k$

$A$ bakerman sells $5$ types of cakes. Profit due to sale of each type of cake is respectively $Rs \ 2$,$Rs \ 2.5$,$Rs \ 3$,$Rs \ 1.5$ and $Rs \ 1$. The demands for these cakes are $20 \%$,$5 \%$,$10 \%$,$50 \%$ and $15 \%$ respectively. Then the expected profit per cake is:

Similar Questions

Let $X$ be a discrete random variable. The probability distribution of $X$ is given below:
$X$ $30$ $10$ $-10$
$P(X)$ $\frac{1}{5}$ $A$ $B$

If $E(X) = 4$,then the value of $AB$ is equal to:

An unbiased die is tossed until a number greater than $4$ appears. The probability that an even number of tosses is needed is

The following table shows the probability distribution of smart phones sold in a shop per day:
Number of smart phones $(x)$ $0$ $1$ $2$ $3$ $4$ $5$
Probability $(P(x))$ $k$ $0.3$ $0.15$ $0.15$ $0.1$ $2k$

Then $E(x) = ?$

When an unfair dice is thrown,the probability of getting a number $k$ on it is $P(X=k)=k^2 P$,where $k=1, 2, 3, 4, 5, 6$ and $X$ is the random variable denoting a number on the dice,then the mean of $X$ is

The probability distribution of a random variable $X$ is given by

$X=x_i$ $0$ $1$ $2$ $3$ $4$

$P(X=x_i)$ $0.4$ $0.3$ $0.1$ $0.1$ $0.1$

Then the variance of $X$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module