$A$ random variable $X$ has the following probability distribution:
$X = x$ $1$ $2$ $3$ $4$ $5$ $6$ $P(X = x)$ $k$ $3k$ $5k$ $7k$ $8k$ $k$
Then $P(2 \leq X < 5) = $
| $X = x$ | $1$ | $2$ | $3$ | $4$ | $5$ | $6$ |
| $P(X = x)$ | $k$ | $3k$ | $5k$ | $7k$ | $8k$ | $k$ |
Then $P(2 \leq X < 5) = $
- A$\frac{7}{25}$
- B$\frac{3}{5}$
- C$\frac{24}{25}$
- D$\frac{23}{25}$
Explore More
Similar Questions
If a discrete random variable $X$ takes the values $1, 2, 3, 4$ such that $2P(X = 1) = 3P(X = 2) = P(X = 3) = 5P(X = 4)$, then $P(X = 4) = ...$ (in $61$)
DifficultMHT CET 2026
View SolutionLet the mean and the standard deviation of the probability distribution be $\mu$ and $\sigma$,respectively. If $\sigma - \mu = 2$,then $\sigma + \mu$ is equal to:
$X$ $\alpha$ $1$ $0$ $-3$ $P(X)$ $\frac{1}{3}$ $K$ $\frac{1}{6}$ $\frac{1}{4}$
| $X$ | $\alpha$ | $1$ | $0$ | $-3$ |
| $P(X)$ | $\frac{1}{3}$ | $K$ | $\frac{1}{6}$ | $\frac{1}{4}$ |
DifficultJEE MAIN 2024
View SolutionSuppose three coins are tossed simultaneously. If $X$ denotes the number of heads,then the probability distribution of $X$ is:
If the probability function of a discrete random variable $X$ is $P(X=r) = r/k$ for $r = 1, 2, 3, 4, 5$, then $P(X=2 \text{ or } X=k/3)$ is equal to:
The following is the probability distribution of $X$:
$X$ $0$ $1$ $2$ $3$ $P(X=x)$ $\frac{1+p}{5}$ $\frac{2-2p}{5}$ $\frac{2-p}{5}$ $\frac{2p}{5}$
For a minimum value of $p$,the value of $5 E(X)$ is:
| $X$ | $0$ | $1$ | $2$ | $3$ |
|---|---|---|---|---|
| $P(X=x)$ | $\frac{1+p}{5}$ | $\frac{2-2p}{5}$ | $\frac{2-p}{5}$ | $\frac{2p}{5}$ |
For a minimum value of $p$,the value of $5 E(X)$ is:
Vedclass Products
For Students
Vedclass Test Series
Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.
Start Free TrialFor Teachers
Exam Paper Generator
Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.
Try FreeFor Institutes
Online Exam Module
Live online exams with unlimited students, 360° analytics & white-label branding.
See Demo