PS is the median of the triangle with vertice | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(C) $S$ is the midpoint of $QR = \left(\frac{6+7}{2}, \frac{-1+3}{2}\right) = \left(\frac{13}{2}, 1\right)$.Slope of $PS = \frac{2-1}{2-\frac{13}{2}}

Vedclass · Accepted Answer

$\frac{-7}{2}, \frac{-7}{9}$

Vedclass · Answer

(C) $S$ is the midpoint of $QR = \left(\frac{6+7}{2}, \frac{-1+3}{2}\right) = \left(\frac{13}{2}, 1\right)$.Slope of $PS = \frac{2-1}{2-\frac{13}{2}} = \frac{1}{-\frac{9}{2}} = -\frac{2}{9}$.The line is parallel to $PS$,so its slope is $m = -\frac{2}{9}$.The equation of the line passing through $(1, -1)$ with slope $m = -\frac{2}{9}$ is $y - (-1) = -\frac{2}{9}(x - 1)$.$9(y + 1) = -2(x - 1)$ $\Rightarrow 9y + 9 = -2x + 2$ $\Rightarrow 2x + 9y + 7 = 0$.To find the $X$-intercept,set $y = 0$: $2x + 7 = 0 \Rightarrow x = -\frac{7}{2}$.To find the $Y$-intercept,set $x = 0$: $9y + 7 = 0 \Rightarrow y = -\frac{7}{9}$.Thus,the intercepts are $-\frac{7}{2}$ and $-\frac{7}{9}$.

$PS$ is the median of the triangle with vertices at $P(2, 2)$,$Q(6, -1)$,and $R(7, 3)$. The intercepts on the coordinate axes of the line passing through point $(1, -1)$ and parallel to $PS$ are respectively:

Similar Questions

Reduce the equation $\sqrt{3} x + y - 8 = 0$ into normal form. Find the values of $p$ and $\omega$.

The equation of the straight line whose slope is $\frac{-2}{3}$ and which divides the line segment joining $(1, 2)$ and $(-3, 5)$ in the ratio $4:3$ externally is

The polar equation of the line perpendicular to the line $\sin \theta - \cos \theta = \frac{1}{r}$ and passing through the point $\left(2, \frac{\pi}{6}\right)$ is

$A$ line $AB$ passes through the origin $(0, 0)$ and is perpendicular to the line $CD$ given by $3x + 4y + 6 = 0$. The equation of line $AB$ is:

The equation of the line,which bisects the line segment joining the points $(2, -19)$ and $(6, 1)$ and is perpendicular to the line joining the points $(-1, 3)$ and $(5, -1)$,is

Vedclass Test Series

Exam Paper Generator

Online Exam Module