tan 1^{circ} times tan 2^{circ} times tan 3^{ | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) We know that $	an(90^{\circ} - 	heta) = \cot 	heta$. The given expression is $P = 	an 1^{\circ} 	an 2^{\circ} 	an 3^{\circ} \cdots 	an 44^{

Vedclass · Accepted Answer

$1$

Vedclass · Answer

(B) We know that $	an(90^{\circ} - 	heta) = \cot 	heta$. The given expression is $P = 	an 1^{\circ} 	an 2^{\circ} 	an 3^{\circ} \cdots 	an 44^{\circ} 	an 45^{\circ} 	an 46^{\circ} \cdots 	an 88^{\circ} 	an 89^{\circ}$. We can write $	an 89^{\circ} = 	an(90^{\circ} - 1^{\circ}) = \cot 1^{\circ}$,$	an 88^{\circ} = \cot 2^{\circ}$,and so on. Thus,$P = (	an 1^{\circ} \cot 1^{\circ}) 	imes (	an 2^{\circ} \cot 2^{\circ}) 	imes \cdots 	imes (	an 44^{\circ} \cot 44^{\circ}) 	imes 	an 45^{\circ}$. Since $	an 	heta 	imes \cot 	heta = 1$ and $	an 45^{\circ} = 1$,we have $P = 1 	imes 1 	imes \cdots 	imes 1 	imes 1 = 1$.

$\tan 1^{\circ} \times \tan 2^{\circ} \times \tan 3^{\circ} \times \cdots \times \tan 89^{\circ} = $

Similar Questions

If $\cos(\alpha + \beta) = 0$,then $\sin(\alpha + 2\beta) =$

If $x \cos \theta = y \cos \left(\theta + \frac{2 \pi}{3}\right) = z \cos \left(\theta + \frac{4 \pi}{3}\right)$,then $\frac{1}{x} + \frac{1}{y} + \frac{1}{z} = $

Identify the symbol representing the alpha character: $ \alpha $

Find the value of the trigonometric function $\tan \frac{19 \pi}{3}$.

The value of $\sin ^2 \frac{\pi}{8} + \sin ^2 \frac{3\pi}{8} + \sin ^2 \frac{5\pi}{8} + \sin ^2 \frac{7\pi}{8}$ is

Vedclass Test Series

Exam Paper Generator

Online Exam Module