$A$ capacitor of $50 \mu F$ is connected to an a.c. source $e = 220 \sin(50t)$ (where $e$ is in volts and $t$ is in seconds). The value of the peak current is:

  • A
    $0.55 \sqrt{2} \text{ A}$
  • B
    $\sqrt{2} \text{ A}$
  • C
    $\frac{\sqrt{2}}{0.55} \text{ A}$
  • D
    $0.55 \text{ A}$

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