$A$ metal rod of weight $W$ is supported by two parallel knife-edges $A$ and $B$. The rod is in equilibrium in a horizontal position. The distance between the two knife-edges is $r$. The centre of mass of the rod is at a distance $x$ from $A$. The normal reaction on $A$ is
- A$\frac{W \cdot r}{x}$
- B$\frac{W \cdot x}{r}$
- C$\frac{W \cdot(r-x)}{x}$
- D$\frac{W \cdot(r-x)}{r}$
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