(B) In an elastic collision,both linear momentum and kinetic energy are conserved.Since the collision is elastic,the total kinetic energy before the c

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(B) In an elastic collision,both linear momentum and kinetic energy are conserved.Since the collision is elastic,the total kinetic energy before the collision is equal to the total kinetic energy after the collision.Let $v_2$ be the speed of the second block after the collision.Initial kinetic energy $KE_i = \frac{1}{2}mv^2 + \frac{1}{2}m(0)^2 = \frac{1}{2}mv^2$.Final kinetic energy $KE_f = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2$.Equating $KE_i = KE_f$:$\frac{1}{2}mv^2 = \frac{1}{2}mv_1^2 + \frac{1}{2}mv_2^2$Dividing by $\frac{1}{2}m$:$v^2 = v_1^2 + v_2^2$$v_2^2 = v^2 - v_1^2$$v_2 = \sqrt{v^2 - v_1^2}$.

Class 11 Physics Work, Energy, Power and Collision Elastic Collision

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$A$ block of mass $m$ moving on a frictionless surface at speed $v$ collides elastically with a block of the same mass,initially at rest. Now,the first block moves at an angle $\theta$ with its initial direction and has speed $v_1$. The speed of the second block after the collision is

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A
$\sqrt{v_1^2-v^2}$
B
$\sqrt{v^2-v_1^2}$
C
$\sqrt{v^2+v_1^2}$
D
$\sqrt{v-v_1}$

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Work, Energy, Power and Collision

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Elastic Collision

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$A$ neutron travelling with a velocity $v$ and kinetic energy $E$ collides perfectly elastically head-on with the nucleus of an atom of mass number $A$ at rest. The fraction of total energy retained by the neutron is

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$A$ neutron moving with velocity $u$ collides elastically with an atom of mass number $A$. If the collision is head-on and the initial kinetic energy of the neutron is $E$, then the final kinetic energy of the neutron after the collision is:

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After a head-on elastic collision between two balls of equal masses,one is observed to have a speed of $3\,m/s$ along the positive $x$-axis and the other has a speed of $2\,m/s$ along the negative $x$-axis. What were the original velocities of the balls?

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$A$ sphere of mass $0.1\,kg$ is attached to a cord of $1\,m$ length. Starting from the height of its point of suspension,this sphere hits a block of the same mass at rest on a frictionless table. If the impact is elastic,then the kinetic energy of the block after the collision is ............. $J$.

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$A$ block of mass $m$ moving on a frictionless surface at speed $v$ collides elastically with a block of the same mass,initially at rest. Now,the first block moves at an angle $\theta$ with its initial direction and has speed $v_1$. The speed of the second block after the collision is

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$A$ sphere of mass $M$ moving with velocity $u$ undergoes a perfectly elastic head-on collision with another sphere of mass $m$ at rest. After the collision,their velocities are $V$ and $v$ respectively. Find the value of $v$.

$A$ neutron travelling with a velocity $v$ and kinetic energy $E$ collides perfectly elastically head-on with the nucleus of an atom of mass number $A$ at rest. The fraction of total energy retained by the neutron is

$A$ neutron moving with velocity $u$ collides elastically with an atom of mass number $A$. If the collision is head-on and the initial kinetic energy of the neutron is $E$, then the final kinetic energy of the neutron after the collision is:

After a head-on elastic collision between two balls of equal masses,one is observed to have a speed of $3\,m/s$ along the positive $x$-axis and the other has a speed of $2\,m/s$ along the negative $x$-axis. What were the original velocities of the balls?

$A$ sphere of mass $0.1\,kg$ is attached to a cord of $1\,m$ length. Starting from the height of its point of suspension,this sphere hits a block of the same mass at rest on a frictionless table. If the impact is elastic,then the kinetic energy of the block after the collision is ............. $J$.

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