$A$ particle of mass $m$ is projected with velocity $v$ making an angle of $45^{\circ}$ with the horizontal. When the particle lands on the level ground,the magnitude of the change in its momentum will be

  • A
    $2 m v$
  • B
    $m v / \sqrt{2}$
  • C
    $m v \sqrt{2}$
  • D
    zero

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