$A$ circuit has self-inductance $L$ and carries a current $I$. To prevent sparking when the circuit is switched off,a capacitor which can withstand potential difference $V$ is used. The least capacitance is
- A$\frac{IV}{L}$
- B$L\left(\frac{V}{I}\right)^2$
- C$L\left(\frac{I}{V}\right)^2$
- D$\frac{LI}{V}$
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