A copper ring is held horizontally and a bar | vedclass

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Question

(B) According to Lenz's Law,when a bar magnet falls through a copper ring,the changing magnetic flux through the ring induces an electromotive force $

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less than acceleration due to gravity.

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(B) According to Lenz's Law,when a bar magnet falls through a copper ring,the changing magnetic flux through the ring induces an electromotive force $(EMF)$ and a corresponding eddy current in the ring.This induced current creates a magnetic field that opposes the change in magnetic flux that produced it.As the magnet enters the ring,the induced magnetic field exerts an upward repulsive force on the magnet.As the magnet leaves the ring,the induced magnetic field exerts an upward attractive force on the magnet.In both cases,the induced magnetic force acts in a direction opposite to the motion of the magnet (upwards),while gravity acts downwards.Therefore,the net acceleration of the magnet is $a = g - a_{induced}$,which is less than the acceleration due to gravity $(g)$.

$A$ copper ring is held horizontally and a bar magnet is dropped through the ring with its length along the axis of the ring. The acceleration of the falling magnet while it is passing through the ring is

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