(A) According to Faraday's law of electromagnetic induction,the induced electromotive force $(e)$ in a coil of $n$ turns is given by $e = -n \frac{d\p

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$\frac{4 n(\phi_1 - \phi_2)}{5 Rt}$

(A) According to Faraday's law of electromagnetic induction,the induced electromotive force $(e)$ in a coil of $n$ turns is given by $e = -n \frac{d\phi}{dt}$.For a finite change in flux from $\phi_1$ to $\phi_2$ in time $t$,the average induced emf is $|e| = n \frac{|\phi_2 - \phi_1|}{t} = \frac{n(\phi_1 - \phi_2)}{t}$.The total resistance of the circuit is $R_{total} = R + R/4 = \frac{5R}{4}$.Using Ohm's law,the induced current $I$ is given by $I = \frac{|e|}{R_{total}}$.Substituting the values,$I = \frac{n(\phi_1 - \phi_2) / t}{5R / 4} = \frac{4n(\phi_1 - \phi_2)}{5Rt}$.

Class 12 Physics Electromagnetic Induction Faraday's and Lenz's Law

Medium

$A$ coil of $n$ turns and resistance $R \Omega$ is connected in series with a resistance $R/4$. The combination is moved for time $t$ seconds through a magnetic flux change from $\phi_1$ to $\phi_2$. The induced current in the circuit is:

MHT CET 2025 All MHT CET

A
$\frac{4 n(\phi_1 - \phi_2)}{5 Rt}$
B
$\frac{n(\phi_1 - \phi_2)}{5 Rt}$
C
$\frac{4 n(\phi_1 - \phi_2)}{Rt}$
D
$\frac{5 n(\phi_1 - \phi_2)}{4 Rt}$

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Faraday's and Lenz's Law

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$A$ coil of $n$ turns and resistance $R \Omega$ is connected in series with a resistance $R/4$. The combination is moved for time $t$ seconds through a magnetic flux change from $\phi_1$ to $\phi_2$. The induced current in the circuit is:

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The total emf induced in a closely wound coil of $N$ turns in which the magnetic flux linked with the coil is changing at the rate $\frac{d \phi_{B}}{dt}$ is

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Assertion $(A):$ The bar magnet falling vertically along the axis of the horizontal coil will have an acceleration less than $g$.
Reason $(R):$ Clockwise current is induced in the coil.