$A$ straight wire of length $0.5 \ m$ and carrying a current of $1.2 \ A$ is placed in a uniform magnetic field of induction $2 \ T$. The magnetic field is perpendicular to the length of the wire. What is the force acting on the wire (in $N$)? $[\sin 90^{\circ} = 1]$

As shown in the figure, a wire is bent to form a $D$-shaped loop carrying current $I$, where the curved part is a semi-circle of radius $R$. The loop is placed in a uniform magnetic field $\overrightarrow{B}$, which is directed into the plane of the paper. The net magnetic force on the closed loop is:

What is the force per unit length between the two wires shown in the figure? [${\mu _0} = 4\pi \times {10^{ - 7}} \text{ T}\,m/A$]

As shown in the figure, a uniform straight wire of length $30 \sqrt{3} \text{ cm}$ is bent in the form of an equilateral triangle $ABC$. $A$ uniform magnetic field $2 \text{ T}$ is applied parallel to the side $BC$. If the current through the wire is $2 \text{ A}$, the magnitude of the force on the side $AC$ is ($\overline{B}$ represents the direction of the magnetic field).

An arbitrarily shaped closed coil is made of a wire of length $L$ and a current $I$ ampere is flowing in it. If the plane of the coil is perpendicular to a uniform magnetic field $\vec{B}$, the net magnetic force on the coil is

$A$ conducting wire $PQ$ carries a current $10 \ A$ as shown in the figure. It is placed in a uniform magnetic field $5 \ T$ which is acting normally outwards from the paper. The net force experienced by the wire is: