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Question

(B) charged particle moving in a circular path acts like a current-carrying loop.Let $q = 100e$ be the charge and $f = 1 \ Hz$ be the frequency of rot

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$10^{-17} \mu_0$

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(B) charged particle moving in a circular path acts like a current-carrying loop.Let $q = 100e$ be the charge and $f = 1 \ Hz$ be the frequency of rotation.The equivalent current $I$ is given by $I = q 	imes f = 100e 	imes 1 = 100e$.Given $e = 1.6 	imes 10^{-19} \ C$ and radius $r = 0.8 \ m$.The magnetic field at the center of a circular loop is $B = \frac{\mu_0 I}{2r}$.Substituting the values:$B = \frac{\mu_0 	imes 100 	imes 1.6 	imes 10^{-19}}{2 	imes 0.8}$$B = \frac{\mu_0 	imes 160 	imes 10^{-19}}{1.6}$$B = \mu_0 	imes 100 	imes 10^{-19} = 10^{-17} \mu_0$.

$A$ particle carrying a charge equal to $100$ times the charge on an electron is rotating one rotation per second in a circular path of radius $0.8 \ m$. The value of magnetic field produced at the centre will be $(\mu_0 = \text{permeability of vacuum})$

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