A paper disc of radius R from which a circula | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(B) The surface tension force acts along the boundaries of the disc in contact with the liquid.There are two boundaries: the outer circumference of ra

Vedclass · Accepted Answer

$2 \pi(R+r) T$

Vedclass · Answer

(B) The surface tension force acts along the boundaries of the disc in contact with the liquid.There are two boundaries: the outer circumference of radius $R$ and the inner circumference of the hole of radius $r$.The force due to surface tension on the outer boundary is $F_1 = T 	imes (2 \pi R)$.The force due to surface tension on the inner boundary is $F_2 = T 	imes (2 \pi r)$.Both forces act to pull the disc towards the liquid surface (or inward towards the center of the respective circles).The total force on the disc due to surface tension is the sum of the magnitudes of these forces:$F_{total} = F_1 + F_2 = 2 \pi RT + 2 \pi rT = 2 \pi (R + r) T$.

$A$ paper disc of radius $R$ from which a circular hole of radius $r$ is cut out,is floating in a liquid of surface tension $T$. The force on the disc due to surface tension will be

Similar Questions

$A$ square frame of each side $L$ is dipped in a soap solution and taken out. The force acting on the film formed is ($T$ = surface tension of soap solution). (in $TL$)

Work of $3.0 \times 10^{-4} \, J$ is required to be done in increasing the size of a soap film from $10 \, cm \times 6 \, cm$ to $10 \, cm \times 11 \, cm$. The surface tension of the film is

$A$ liquid is coming out from a vertical tube. The relation between the weight of the drop $W$,surface tension of the liquid $T$,and radius of the tube $r$ is given by,if the angle of contact is zero.

Oil spreads over the surface of water whereas water does not spread over the surface of the oil,due to

Surface tension may be defined as

Vedclass Test Series

Exam Paper Generator

Online Exam Module