$A$ capillary tube stands with its lower end dipped into a liquid for which the angle of contact is $90^{\circ}$. The liquid will

  • A
    neither rise nor fall.
  • B
    get depressed only.
  • C
    rise only.
  • D
    rise up to the top of the tube.

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Three liquids have the same surface tension and densities $\rho_1, \rho_2$ and $\rho_3$ $(\rho_1 < \rho_2 < \rho_3)$. In three identical capillaries, the rise of liquid is the same. The corresponding angles of contact $\theta_1, \theta_2$ and $\theta_3$ are related as:

The height of a liquid column raised in a capillary tube of a certain radius when dipped in liquid $A$ vertically is $5 \ cm$. If the tube is dipped in a similar manner in another liquid $B$ with surface tension and density double the values of liquid $A$,the height of the liquid column raised in liquid $B$ would be $........ \ m$.

Water rises in a capillary tube of radius $r$ up to a height $h$. The mass of water in the capillary is $m$. What will be the mass of water that rises in a capillary tube of radius $\frac{r}{4}$?

If water rises in a capillary tube up to $3 \, cm$,what is the diameter of the capillary tube? (Surface tension of water $T = 7.2 \times 10^{-2} \, N/m$,density $\rho = 10^3 \, kg/m^3$,$g = 10 \, m/s^2$)

Water rises to a height of $10 \, cm$ in a capillary tube and mercury falls to a depth of $3.1 \, cm$ in the same capillary tube. If the density of mercury is $13.6 \, g/cm^3$ and the angle of contact for mercury is $135^{\circ}$,the approximate ratio of surface tensions of water and mercury is

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