$A$ rubber ball is taken into the deep sea such that its volume decreases by $x \%$. The bulk modulus of rubber is $K$ and the density of sea water is $\rho$. The depth $h$ to which the rubber ball is taken is proportional to $(g = \text{acceleration due to gravity})$:

The bulk modulus of a spherical object is '$B$'. If it is subjected to uniform pressure '$P$',the fractional decrease in radius is

$A$ solid sphere of radius $R$ made of a material of bulk modulus $K$ is surrounded by a liquid in a cylindrical container. $A$ massless piston of area $A$ floats on the surface of the liquid. When a mass $m$ is placed on the piston to compress the liquid,the fractional change in the radius of the sphere $\delta R/R$ is

The increase in pressure required to decrease the $200 \, L$ volume of a liquid by $0.008 \, \%$ in $kPa$ is (Bulk modulus of the liquid $= 2100 \, MPa$)

The Mariana Trench is located in the Pacific Ocean,and at one place it is nearly $11 \; km$ beneath the surface of the water. The water pressure at the bottom of the trench is about $1.1 \times 10^{8} \; Pa$. $A$ steel ball of initial volume $0.32 \; m^{3}$ is dropped into the ocean and falls to the bottom of the trench. What is the change in the volume of the ball when it reaches the bottom? (Bulk modulus of steel $B = 1.6 \times 10^{11} \; N/m^{2}$)

$A$ spherical ball of volume $2000 \text{ cm}^3$ is subjected to a hydraulic pressure of $15 \text{ atm}$. If the change in volume is $5 \times 10^{-2} \text{ cm}^3$,the bulk modulus of the material of the spherical ball is (Given: $1 \text{ atm} = 10^5 \text{ Nm}^{-2}$)