A particle moves along a circular path with d | vedclass

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Question

(C) The angular momentum $\overrightarrow{L}$ of a particle moving in a circular path is given by $\overrightarrow{L} = \overrightarrow{r} 	imes \ove

Vedclass · Accepted Answer

the direction of angular momentum remains constant.

Vedclass · Answer

(C) The angular momentum $\overrightarrow{L}$ of a particle moving in a circular path is given by $\overrightarrow{L} = \overrightarrow{r} 	imes \overrightarrow{p} = \overrightarrow{r} 	imes m\overrightarrow{v}$.Since the particle moves in a circular path,the position vector $\overrightarrow{r}$ and the velocity vector $\overrightarrow{v}$ are always perpendicular to each other.The direction of the angular momentum vector $\overrightarrow{L}$ is determined by the right-hand rule,which is perpendicular to the plane of the circular motion.As the speed $v$ decreases,the magnitude of the angular momentum $|\overrightarrow{L}| = mvr$ decreases.However,because the particle remains in the same plane of motion,the direction of the angular momentum vector remains constant.

$A$ particle moves along a circular path with decreasing speed. Hence

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