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(C) Let the atomic number of $A$ be $Z$ and its mass number be $A_{mass}$.$1$. In the first decay: $A \rightarrow B + {}_{2}^{4}He$. The element $B$ w

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$A$ and $C$ are isotopes.

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(C) Let the atomic number of $A$ be $Z$ and its mass number be $A_{mass}$.$1$. In the first decay: $A \rightarrow B + {}_{2}^{4}He$. The element $B$ will have atomic number $(Z-2)$ and mass number $(A_{mass}-4)$.$2$. In the second decay: $B \rightarrow C + 2e^{-}$. The emission of two electrons (beta particles) increases the atomic number by $2$ but does not change the mass number.$3$. Therefore,the atomic number of $C$ is $(Z-2) + 2 = Z$ and its mass number is $(A_{mass}-4)$.$4$. Comparing $A$ (atomic number $Z$,mass number $A_{mass}$) and $C$ (atomic number $Z$,mass number $A_{mass}-4$),they have the same atomic number but different mass numbers. Thus,$A$ and $C$ are isotopes.

$A$ radioactive element $A$ decays into radioactive element $C$ by the following processes in succession.
$A \rightarrow B + {}_{2}^{4}He$
$B \rightarrow C + 2e^{-}$
Then elements

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$A$ radioactive element $A$ decays into radioactive element $C$ by the following processes in succession.$A \rightarrow B + {}_{2}^{4}He$$B \rightarrow C + 2e^{-}$Then elements