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(D) In simple harmonic motion $(SHM)$,a particle oscillates between two extreme positions,$-A$ and $+A$,passing through the mean position $0$.One comp

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$4A$

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(D) In simple harmonic motion $(SHM)$,a particle oscillates between two extreme positions,$-A$ and $+A$,passing through the mean position $0$.One complete periodic time $(T)$ represents one full oscillation.Starting from the mean position $(0)$: $1$. The particle moves from $0$ to $+A$ (distance = $A$).$2$. The particle moves from $+A$ back to $0$ (distance = $A$).$3$. The particle moves from $0$ to $-A$ (distance = $A$).$4$. The particle moves from $-A$ back to $0$ (distance = $A$).Total distance travelled in one periodic time = $A + A + A + A = 4A$.

$A$ particle executes simple harmonic motion with an amplitude '$A$'. The distance travelled by it in one periodic time is

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