A simple microscope is used to see an object | vedclass

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(B) The magnifying power $(M)$ of a simple microscope is given by the formula: $M = 1 + \frac{D}{f}$, where $D$ is the least distance of distinct visi

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Magnifying power decreases.

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(B) The magnifying power $(M)$ of a simple microscope is given by the formula: $M = 1 + \frac{D}{f}$, where $D$ is the least distance of distinct vision and $f$ is the focal length of the lens.According to Cauchy's formula, the refractive index $(\mu)$ of a material depends on the wavelength $(\lambda)$ as $\mu \propto \frac{1}{\lambda^2}$. Since the wavelength of red light $(\lambda_r)$ is greater than the wavelength of blue light $(\lambda_b)$, the refractive index for red light is less than that for blue light $(\mu_r From the lens maker's formula, $\frac{1}{f} = (\mu - 1) \left( \frac{1}{R_1} - \frac{1}{R_2} \right)$, we see that $f \propto \frac{1}{\mu - 1}$. Since $\mu_r  f_b$.As the magnifying power $M = 1 + \frac{D}{f}$, an increase in focal length $(f)$ leads to a decrease in the magnifying power. Therefore, when changing from blue light to red light, the magnifying power decreases.

$A$ simple microscope is used to see an object first in blue light and then in red light. Due to the change from blue to red light, what is the effect on its magnifying power?

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