A transparent glass cube of length 24 ,cm has | vedclass

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(A) Let the distance of the air bubble from the first surface be $l_1$ and from the second surface be $l_2$. The total length of the cube is $L = 24 \

Vedclass · Accepted Answer

$15$

Vedclass · Answer

(A) Let the distance of the air bubble from the first surface be $l_1$ and from the second surface be $l_2$. The total length of the cube is $L = 24 \,cm$. Thus, $l_1 + l_2 = 24 \,cm$, which implies $l_2 = 24 - l_1$.The formula for apparent depth is given by $\mu = \frac{	ext{Real depth}}{	ext{Apparent depth}}$.For the first surface:$\mu = \frac{l_1}{10} \quad \dots(i)$For the second surface:$\mu = \frac{l_2}{6} = \frac{24 - l_1}{6} \quad \dots(ii)$Equating $(i)$ and $(ii)$:$\frac{l_1}{10} = \frac{24 - l_1}{6}$$6l_1 = 10(24 - l_1)$$6l_1 = 240 - 10l_1$$16l_1 = 240$$l_1 = \frac{240}{16} = 15 \,cm$Therefore, the distance of the air bubble from the first surface is $15 \,cm$.

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