(B) Let the distance of the source from the surface be $x$. The thickness of the glass slab is $d = 5 \ cm$,and its refractive index is $\mu = 1.6$.Th

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(B) Let the distance of the source from the surface be $x$. The thickness of the glass slab is $d = 5 \ cm$,and its refractive index is $\mu = 1.6$.The time taken by light to travel a distance $x$ in air (where speed is $c$) is $t_1 = \frac{x}{c}$.The time taken by light to travel through the glass slab of thickness $d$ (where speed is $v = \frac{c}{\mu}$) is $t_2 = \frac{d}{v} = \frac{d}{c/\mu} = \frac{\mu d}{c}$.According to the problem,$t_1 = t_2$,so:$\frac{x}{c} = \frac{\mu d}{c}$$x = \mu d$$x = 1.6 \times 5 \ cm = 8 \ cm$.Therefore,the distance of the source from the surface is $8 \ cm$.

Class 12 Physics Ray Optics and Optical Instruments Refraction through Plane Surface and Glass Slab

Medium

$A$ ray of light is incident normally on a glass slab of thickness $5 \ cm$ and refractive index $1.6$. The time taken by a ray to travel from the source to the surface of the slab is the same as the time taken to travel through the glass slab. The distance of the source from the surface is: (in $cm$)

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A
$4$
B
$8$
C
$12$
D
$16$

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Class 12

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Ray Optics and Optical Instruments

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Refraction through Plane Surface and Glass Slab

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