A solid sphere has mass M and radius R. Its m | vedclass

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(D) Concept: Application of the parallel axis theorem.The moment of inertia of a solid sphere about an axis passing through its centre is:$I_{	ext{cm

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$\frac{13 MR^2}{20}$

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(D) Concept: Application of the parallel axis theorem.The moment of inertia of a solid sphere about an axis passing through its centre is:$I_{	ext{cm}} = \frac{2}{5} MR^2$According to the parallel axis theorem,the moment of inertia $I$ about an axis parallel to the one passing through the centre of mass at a distance $d$ is given by:$I = I_{	ext{cm}} + Md^2$Here,the distance $d = \frac{R}{2}$.Substituting the values:$I = \frac{2}{5} MR^2 + M\left(\frac{R}{2}ight)^2$$I = \frac{2}{5} MR^2 + \frac{1}{4} MR^2$$I = \left(\frac{8 + 5}{20}ight) MR^2$$I = \frac{13}{20} MR^2$

$A$ solid sphere has mass $M$ and radius $R$. Its moment of inertia about a parallel axis passing through a point at a distance $\frac{R}{2}$ from its centre is

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