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(B) The number of photoelectrons emitted per second is directly proportional to the intensity of the incident light.For a point source of light,the in

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number of electrons emitted is a quarter of the initial number

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(B) The number of photoelectrons emitted per second is directly proportional to the intensity of the incident light.For a point source of light,the intensity $I$ follows the inverse square law: $I \propto \frac{1}{d^2}$,where $d$ is the distance from the source.When the distance is doubled $(d' = 2d)$,the new intensity $I'$ becomes $I' = \frac{I}{2^2} = \frac{I}{4}$.Since the number of photoelectrons emitted is directly proportional to the intensity,the number of photoelectrons emitted becomes one-fourth of the initial number.The energy of each emitted electron depends on the frequency of the incident light,not on its intensity. Therefore,the energy of each emitted electron remains unchanged.

$A$ photoelectric cell is illuminated by a point source of light $1 \ m$ away. When the source is shifted to $2 \ m$,then:

Similar Questions

The threshold frequency for a metal is $10^{15} \ Hz$. Choose the correct statement when light of wavelength $4000 \ \mathring A$ is incident on it.

Threshold frequency for a metal is $15 \times 10^{14} \, Hz$. The light of wavelength $6000 \, \text{Å}$ falls on the metal surface. Then photoelectrons [velocity of light in air, $c = 3 \times 10^8 \, m/s$]:

By increasing the intensity of incident light, keeping the frequency $(v > v_0)$ fixed on the surface of a metal:

Assertion : The photoelectrons produced by a monochromatic light beam incident on a metal surface have a spread in their kinetic energies.
Reason : The work function of the metal varies as a function of depth from the surface.

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