A stationary object at 4^{circ} C and weighin | vedclass

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(C) The potential energy of the object at height $h$ is converted into heat energy upon impact. Given: Mass $m = 3.5 \ kg$,height $h = 2000 \ m$,$g =

Vedclass · Accepted Answer

$200 \ g$

Vedclass · Answer

(C) The potential energy of the object at height $h$ is converted into heat energy upon impact. Given: Mass $m = 3.5 \ kg$,height $h = 2000 \ m$,$g = 10 \ m/s^2$,Latent heat $L = 3.5 	imes 10^5 \ J/kg$. The potential energy $PE = mgh = 3.5 	imes 10 	imes 2000 = 70,000 \ J$. The heat required to melt a mass $m'$ of ice is $Q = m'L$. Since the object comes to rest,all potential energy is converted into heat: $mgh = m'L$. $70,000 = m' 	imes 3.5 	imes 10^5$. $m' = \frac{70,000}{3.5 	imes 10^5} = \frac{7 	imes 10^4}{3.5 	imes 10^5} = 2 	imes 10^{-1} \ kg = 0.2 \ kg$. Converting to grams: $0.2 \ kg = 200 \ g$.

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