$A$ cylindrical rod has temperatures $T_1$ and $T_2$ at its ends. The rate of flow of heat is $Q_1 \text{ cal s}^{-1}$. If the length and radius of the rod are doubled while keeping the temperatures constant,then the new rate of flow of heat $Q_2$ will be:

  • A
    $Q_2 = \frac{Q_1}{2}$
  • B
    $Q_2 = \frac{Q_1}{4}$
  • C
    $Q_2 = 4 Q_1$
  • D
    $Q_2 = 2 Q_1$

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