(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{d}$,where $\lambda

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decreases with an increase in slit width

(B) The angular width of the central maximum in a single-slit diffraction pattern is given by the formula $\theta = \frac{2\lambda}{d}$,where $\lambda$ is the wavelength of the light and $d$ is the width of the slit.From this relation,it is clear that the angular width $\theta$ is inversely proportional to the slit width $d$ (i.e.,$\theta \propto \frac{1}{d}$).Therefore,as the slit width $d$ increases,the angular width of the central maximum decreases.

Class 12 Physics Wave Optics Single Slit Diffraction of Light

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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decreases with a decrease in slit width
B
decreases with an increase in slit width
C
increases with an increase in slit width
D
may increase or decrease

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$A$ parallel beam of monochromatic light falls normally on a single narrow slit. The angular width of the central maximum in the resulting diffraction pattern

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When you look at a clear blue sky, you see tiny specks and hair-like structures floating in your view, called "floaters". This is basically

The angular width of the central maximum in a single-slit diffraction pattern does not depend on .........

Orange light of wavelength $6000 \times 10^{-10} \ m$ illuminates a single slit of width $0.6 \times 10^{-4} \ m$. The maximum possible number of diffraction minima produced on both sides of the central maximum is $........$

If we observe the single slit Fraunhofer diffraction with wavelength $\lambda$ and slit width $e$,the width of the central maxima is $2\theta$. On decreasing the slit width for the same $\lambda$,what happens to $\theta$?

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