$A$ light wave of wavelength $\lambda$ is incident on a slit of width $d$. The resulting diffraction pattern is observed on a screen at a distance $D$. If the linear width of the principal maxima is equal to the width of the slit,then the distance $D$ is:

  • A
    $\frac{d}{\lambda}$
  • B
    $\frac{2 \lambda}{d}$
  • C
    $\frac{d^{2}}{2 \lambda}$
  • D
    $\frac{2 \lambda^{2}}{d}$

Explore More

Similar Questions

Angular width $(\beta)$ of the central maximum of a diffraction pattern on a single slit does not depend upon

Assertion : Diffraction takes place for all types of waves,mechanical or non-mechanical,transverse or longitudinal.
Reason : Diffraction effects are perceptible only if the wavelength of the wave is comparable to the dimensions of the diffracting device.

The condition for obtaining secondary maxima in the diffraction pattern due to a single slit is:

The phenomenon that explains why light waves do not travel in a straight line is known as .......

Light of wavelength $5000 \, \text{Å}$ is incident on a slit of width $0.1 \, \text{mm}$. Find the width of the central bright fringe on a screen placed at a distance of $2 \, \text{m}$ in $\text{mm}$.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo